Search a number
-
+
110031111001 = 715718730143
BaseRepresentation
bin110011001111001011…
…1011000001101011001
3101112000020221120122101
41212132113120031121
53300320431023001
6122314140323401
710643450004040
oct1463627301531
9345006846571
10110031111001
114273376a289
12193a9243561
13a4b6aa0796
14547b3a1557
152cdebe0a01
hex199e5d8359

110031111001 has 4 divisors (see below), whose sum is σ = 125749841152. Its totient is φ = 94312380852.

The previous prime is 110031110993. The next prime is 110031111013. The reversal of 110031111001 is 100111130011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110031111001 - 23 = 110031110993 is a prime.

It is a super-2 number, since 2×1100311110012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110031111601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7859365065 + ... + 7859365078.

It is an arithmetic number, because the mean of its divisors is an integer number (31437460288).

Almost surely, 2110031111001 is an apocalyptic number.

It is an amenable number.

110031111001 is a deficient number, since it is larger than the sum of its proper divisors (15718730151).

110031111001 is an equidigital number, since it uses as much as digits as its factorization.

110031111001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15718730150.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 110031111001 its reverse (100111130011), we get a palindrome (210142241012).

The spelling of 110031111001 in words is "one hundred ten billion, thirty-one million, one hundred eleven thousand, one".

Divisors: 1 7 15718730143 110031111001