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110031230113 = 715718747159
BaseRepresentation
bin110011001111001011…
…1110101010010100001
3101112000021011122000221
41212132113311102201
53300320443330423
6122314143043041
710643451011230
oct1463627652241
9345007148027
10110031230113
1142733840822
12193a92a0481
13a4b6b12a6c
14547b3d2b17
152cdec15e5d
hex199e5f54a1

110031230113 has 4 divisors (see below), whose sum is σ = 125749977280. Its totient is φ = 94312482948.

The previous prime is 110031230107. The next prime is 110031230137. The reversal of 110031230113 is 311032130011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110031230113 - 213 = 110031221921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110031200113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7859373573 + ... + 7859373586.

It is an arithmetic number, because the mean of its divisors is an integer number (31437494320).

Almost surely, 2110031230113 is an apocalyptic number.

It is an amenable number.

110031230113 is a deficient number, since it is larger than the sum of its proper divisors (15718747167).

110031230113 is an equidigital number, since it uses as much as digits as its factorization.

110031230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15718747166.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 110031230113 its reverse (311032130011), we get a palindrome (421063360124).

The spelling of 110031230113 in words is "one hundred ten billion, thirty-one million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 7 15718747159 110031230113