1100313311131 has 4 divisors (see below), whose sum is σ = 1100315470000. Its totient is φ = 1100311152264.

The previous prime is 1100313311093. The next prime is 1100313311179. The reversal of 1100313311131 is 1311133130011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100313311131 - 2⁷ = 1100313311003 is a prime.

It is a super-2 number, since 2×1100313311131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100313311099 and 1100313311108.

It is not an unprimeable number, because it can be changed into a prime (1100313314131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157690 + ... + 1491808.

It is an arithmetic number, because the mean of its divisors is an integer number (275078867500).

Almost surely, 2^{1100313311131} is an apocalyptic number.

1100313311131 is a deficient number, since it is larger than the sum of its proper divisors (2158869).

1100313311131 is an equidigital number, since it uses as much as digits as its factorization.

1100313311131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2158868.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1100313311131 its reverse (1311133130011), we get a palindrome (2411446441142).

The spelling of 1100313311131 in words is "one trillion, one hundred billion, three hundred thirteen million, three hundred eleven thousand, one hundred thirty-one".