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1100334066649 is a prime number
BaseRepresentation
bin10000000000110001000…
…001010110101111011001
310220012011011200010000121
4100000301001112233121
5121011441010113044
62201253025433241
7142332206150536
oct20006101265731
93805134603017
101100334066649
11394715993234
1215930379b821
137c9b807304c
143b3839c7d8d
151d94ee8d984
hex10031056bd9

1100334066649 has 2 divisors, whose sum is σ = 1100334066650. Its totient is φ = 1100334066648.

The previous prime is 1100334066631. The next prime is 1100334066653. The reversal of 1100334066649 is 9466604330011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 979555575625 + 120778491024 = 989725^2 + 347532^2 .

It is an emirp because it is prime and its reverse (9466604330011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100334066649 - 217 = 1100333935577 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100334066449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550167033324 + 550167033325.

It is an arithmetic number, because the mean of its divisors is an integer number (550167033325).

Almost surely, 21100334066649 is an apocalyptic number.

It is an amenable number.

1100334066649 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100334066649 is an equidigital number, since it uses as much as digits as its factorization.

1100334066649 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 279936, while the sum is 43.

The spelling of 1100334066649 in words is "one trillion, one hundred billion, three hundred thirty-four million, sixty-six thousand, six hundred forty-nine".