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11003410413000 = 233453314382083
BaseRepresentation
bin1010000000011110111001…
…0111100111010111001000
31102221220201120221121110000
42200013232113213113020
52420234441031204000
635222521424323000
72213653524210345
oct240075627472710
942856646847400
1011003410413000
11356257a357755
12129864ba73460
1361a803b54705
142a07d44937cc
15141355cbc000
hexa01ee5e75c8

11003410413000 has 320 divisors, whose sum is σ = 39703784440320. Its totient is φ = 2839589136000.

The previous prime is 11003410412963. The next prime is 11003410413001. The reversal of 11003410413000 is 31401430011.

11003410413000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (11003410413001) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 319959 + ... + 4702041.

It is an arithmetic number, because the mean of its divisors is an integer number (124074326376).

Almost surely, 211003410413000 is an apocalyptic number.

11003410413000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11003410413000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19851892220160).

11003410413000 is an abundant number, since it is smaller than the sum of its proper divisors (28700374027320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11003410413000 is a wasteful number, since it uses less digits than its factorization.

11003410413000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4382147 (or 4382124 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11003410413000 its reverse (31401430011), we get a palindrome (11034811843011).

The spelling of 11003410413000 in words is "eleven trillion, three billion, four hundred ten million, four hundred thirteen thousand".