Base | Representation |
---|---|
bin | 11001000001001101010110… |
… | …000011111010100001100011 |
3 | 112102121011112100121211000001 |
4 | 121001031112003322201203 |
5 | 103410300031010213242 |
6 | 1030005004012440431 |
7 | 32114465216436331 |
oct | 3101152603724143 |
9 | 472534470554001 |
10 | 110034211022947 |
11 | 3207327959a082 |
12 | 1041144a779117 |
13 | 4952248c015c3 |
14 | 1d25981750b51 |
15 | cac397d96eb7 |
hex | 6413560fa863 |
110034211022947 has 2 divisors, whose sum is σ = 110034211022948. Its totient is φ = 110034211022946.
The previous prime is 110034211022899. The next prime is 110034211022951. The reversal of 110034211022947 is 749220112430011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110034211022947 is a prime.
It is not a weakly prime, because it can be changed into another prime (110034211022347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55017105511473 + 55017105511474.
It is an arithmetic number, because the mean of its divisors is an integer number (55017105511474).
Almost surely, 2110034211022947 is an apocalyptic number.
110034211022947 is a deficient number, since it is larger than the sum of its proper divisors (1).
110034211022947 is an equidigital number, since it uses as much as digits as its factorization.
110034211022947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 37.
Adding to 110034211022947 its reverse (749220112430011), we get a palindrome (859254323452958).
The spelling of 110034211022947 in words is "one hundred ten trillion, thirty-four billion, two hundred eleven million, twenty-two thousand, nine hundred forty-seven".
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