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1100365020481 is a prime number
BaseRepresentation
bin10000000000110010110…
…111011011110101000001
310220012020022220201200211
4100000302313123311001
5121012021421123411
62201300053114121
7142333033231126
oct20006267336501
93805208821624
101100365020481
11394731405311
12159312028941
137c9c15c021c
143b387b6474d
151d952a55221
hex10032ddbd41

1100365020481 has 2 divisors, whose sum is σ = 1100365020482. Its totient is φ = 1100365020480.

The previous prime is 1100365020457. The next prime is 1100365020497. The reversal of 1100365020481 is 1840205630011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1073244200625 + 27120819856 = 1035975^2 + 164684^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100365020481 - 213 = 1100365012289 is a prime.

It is a super-2 number, since 2×11003650204812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100365027481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550182510240 + 550182510241.

It is an arithmetic number, because the mean of its divisors is an integer number (550182510241).

Almost surely, 21100365020481 is an apocalyptic number.

It is an amenable number.

1100365020481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100365020481 is an equidigital number, since it uses as much as digits as its factorization.

1100365020481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

The spelling of 1100365020481 in words is "one trillion, one hundred billion, three hundred sixty-five million, twenty thousand, four hundred eighty-one".