Base | Representation |
---|---|
bin | 10000000000110010110… |
… | …111011011110101000001 |
3 | 10220012020022220201200211 |
4 | 100000302313123311001 |
5 | 121012021421123411 |
6 | 2201300053114121 |
7 | 142333033231126 |
oct | 20006267336501 |
9 | 3805208821624 |
10 | 1100365020481 |
11 | 394731405311 |
12 | 159312028941 |
13 | 7c9c15c021c |
14 | 3b387b6474d |
15 | 1d952a55221 |
hex | 10032ddbd41 |
1100365020481 has 2 divisors, whose sum is σ = 1100365020482. Its totient is φ = 1100365020480.
The previous prime is 1100365020457. The next prime is 1100365020497. The reversal of 1100365020481 is 1840205630011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1073244200625 + 27120819856 = 1035975^2 + 164684^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100365020481 - 213 = 1100365012289 is a prime.
It is a super-2 number, since 2×11003650204812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100365027481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550182510240 + 550182510241.
It is an arithmetic number, because the mean of its divisors is an integer number (550182510241).
Almost surely, 21100365020481 is an apocalyptic number.
It is an amenable number.
1100365020481 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100365020481 is an equidigital number, since it uses as much as digits as its factorization.
1100365020481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
The spelling of 1100365020481 in words is "one trillion, one hundred billion, three hundred sixty-five million, twenty thousand, four hundred eighty-one".
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