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1100410430114 = 2550205215057
BaseRepresentation
bin10000000000110101100…
…100101010001010100010
310220012100111100210000002
4100000311210222022202
5121012120032230424
62201304354300002
7142334124216542
oct20006544521242
93805314323002
101100410430114
11394755000236
12159325287602
137c9cab2c128
143b38dbc5322
151d956a24cae
hex1003592a2a2

1100410430114 has 4 divisors (see below), whose sum is σ = 1650615645174. Its totient is φ = 550205215056.

The previous prime is 1100410430111. The next prime is 1100410430137. The reversal of 1100410430114 is 4110340140011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 804510333025 + 295900097089 = 896945^2 + 543967^2 .

It is a super-2 number, since 2×11004104301142 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1100410430111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275102607527 + ... + 275102607530.

Almost surely, 21100410430114 is an apocalyptic number.

1100410430114 is a deficient number, since it is larger than the sum of its proper divisors (550205215060).

1100410430114 is an equidigital number, since it uses as much as digits as its factorization.

1100410430114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 550205215059.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1100410430114 its reverse (4110340140011), we get a palindrome (5210750570125).

The spelling of 1100410430114 in words is "one trillion, one hundred billion, four hundred ten million, four hundred thirty thousand, one hundred fourteen".

Divisors: 1 2 550205215057 1100410430114