Base | Representation |
---|---|
bin | 100000110010111… |
… | …0001100010100001 |
3 | 2211200122012012202 |
4 | 1001211301202201 |
5 | 4223201440111 |
6 | 301105502545 |
7 | 36161266211 |
oct | 10145614241 |
9 | 2750565182 |
10 | 1100421281 |
11 | 515182883 |
12 | 268641a55 |
13 | 146c9a66b |
14 | a620c241 |
15 | 6691ab3b |
hex | 419718a1 |
1100421281 has 2 divisors, whose sum is σ = 1100421282. Its totient is φ = 1100421280.
The previous prime is 1100421239. The next prime is 1100421307. The reversal of 1100421281 is 1821240011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 811965025 + 288456256 = 28495^2 + 16984^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100421281 is a prime.
It is a super-2 number, since 2×11004212812 = 2421853991355361922, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100423281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550210640 + 550210641.
It is an arithmetic number, because the mean of its divisors is an integer number (550210641).
Almost surely, 21100421281 is an apocalyptic number.
It is an amenable number.
1100421281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100421281 is an equidigital number, since it uses as much as digits as its factorization.
1100421281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 20.
The square root of 1100421281 is about 33172.5983456226. The cubic root of 1100421281 is about 1032.4118804545.
Adding to 1100421281 its reverse (1821240011), we get a palindrome (2921661292).
The spelling of 1100421281 in words is "one billion, one hundred million, four hundred twenty-one thousand, two hundred eighty-one".
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