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11004343113 = 319131917467
BaseRepresentation
bin10100011111110100…
…01111001101001001
31001101220121112212110
422033322033031021
5140014102434423
65015541132533
7536461241661
oct121772171511
931356545773
1011004343113
114737734945
1221713ba149
131064ab843a
147656c11a1
1544614b193
hex28fe8f349

11004343113 has 8 divisors (see below), whose sum is σ = 14680135008. Its totient is φ = 7332389984.

The previous prime is 11004343111. The next prime is 11004343127. The reversal of 11004343113 is 31134340011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11004343113 - 21 = 11004343111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11004343113.

It is not an unprimeable number, because it can be changed into a prime (11004343111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 952995 + ... + 964472.

It is an arithmetic number, because the mean of its divisors is an integer number (1835016876).

Almost surely, 211004343113 is an apocalyptic number.

It is an amenable number.

11004343113 is a deficient number, since it is larger than the sum of its proper divisors (3675791895).

11004343113 is a wasteful number, since it uses less digits than its factorization.

11004343113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1919383.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11004343113 its reverse (31134340011), we get a palindrome (42138683124).

The spelling of 11004343113 in words is "eleven billion, four million, three hundred forty-three thousand, one hundred thirteen".

Divisors: 1 3 1913 5739 1917467 5752401 3668114371 11004343113