110044113131441 has 4 divisors (see below), whose sum is σ = 111686562581232. Its totient is φ = 108401663681652.

The previous prime is 110044113131437. The next prime is 110044113131461. The reversal of 110044113131441 is 144131311440011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110044113131441 - 2² = 110044113131437 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110044113131461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 821224724795 + ... + 821224724928.

It is an arithmetic number, because the mean of its divisors is an integer number (27921640645308).

Almost surely, 2^{110044113131441} is an apocalyptic number.

It is an amenable number.

110044113131441 is a deficient number, since it is larger than the sum of its proper divisors (1642449449791).

110044113131441 is an equidigital number, since it uses as much as digits as its factorization.

110044113131441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1642449449790.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 110044113131441 its reverse (144131311440011), we get a palindrome (254175424571452).

The spelling of 110044113131441 in words is "one hundred ten trillion, forty-four billion, one hundred thirteen million, one hundred thirty-one thousand, four hundred forty-one".