11004614353 has 2 divisors, whose sum is σ = 11004614354. Its totient is φ = 11004614352.

The previous prime is 11004614321. The next prime is 11004614359. The reversal of 11004614353 is 35341640011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9815261184 + 1189353169 = 99072^2 + 34487^2 .

It is an emirp because it is prime and its reverse (35341640011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11004614353 - 2⁵ = 11004614321 is a prime.

It is a super-2 number, since 2×11004614353² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11004614359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502307176 + 5502307177.

It is an arithmetic number, because the mean of its divisors is an integer number (5502307177).

Almost surely, 2^11004614353 is an apocalyptic number.

It is an amenable number.

11004614353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004614353 is an equidigital number, since it uses as much as digits as its factorization.

11004614353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

The spelling of 11004614353 in words is "eleven billion, four million, six hundred fourteen thousand, three hundred fifty-three".