Base | Representation |
---|---|
bin | 10000000000111011001… |
… | …111010111010010001011 |
3 | 10220012121010021101112021 |
4 | 100000323033113102023 |
5 | 121012313402323201 |
6 | 2201322032225311 |
7 | 142336360333462 |
oct | 20007317272213 |
9 | 3805533241467 |
10 | 1100505511051 |
11 | 3947a3741a21 |
12 | 15935109b237 |
13 | 7ca1473c93b |
14 | 3b39c6959d9 |
15 | 1d960056ea1 |
hex | 1003b3d748b |
1100505511051 has 4 divisors (see below), whose sum is σ = 1100527355032. Its totient is φ = 1100483667072.
The previous prime is 1100505510997. The next prime is 1100505511057. The reversal of 1100505511051 is 1501155050011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1100505511051 - 221 = 1100503413899 is a prime.
It is a super-2 number, since 2×11005055110512 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1100505511057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10846245 + ... + 10947238.
It is an arithmetic number, because the mean of its divisors is an integer number (275131838758).
Almost surely, 21100505511051 is an apocalyptic number.
1100505511051 is a deficient number, since it is larger than the sum of its proper divisors (21843981).
1100505511051 is an equidigital number, since it uses as much as digits as its factorization.
1100505511051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21843980.
The product of its (nonzero) digits is 625, while the sum is 25.
The spelling of 1100505511051 in words is "one trillion, one hundred billion, five hundred five million, five hundred eleven thousand, fifty-one".
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