110052115114537 has 2 divisors, whose sum is σ = 110052115114538. Its totient is φ = 110052115114536.

The previous prime is 110052115114489. The next prime is 110052115114541. The reversal of 110052115114537 is 735411511250011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84255711586281 + 25796403528256 = 9179091^2 + 5079016^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110052115114537 is a prime.

It is a super-2 number, since 2×110052115114537² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110052115114496 and 110052115114505.

It is not a weakly prime, because it can be changed into another prime (110052115114567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55026057557268 + 55026057557269.

It is an arithmetic number, because the mean of its divisors is an integer number (55026057557269).

Almost surely, 2^{110052115114537} is an apocalyptic number.

It is an amenable number.

110052115114537 is a deficient number, since it is larger than the sum of its proper divisors (1).

110052115114537 is an equidigital number, since it uses as much as digits as its factorization.

110052115114537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21000, while the sum is 37.

Adding to 110052115114537 its reverse (735411511250011), we get a palindrome (845463626364548).

The spelling of 110052115114537 in words is "one hundred ten trillion, fifty-two billion, one hundred fifteen million, one hundred fourteen thousand, five hundred thirty-seven".