110053314441 has 48 divisors (see below), whose sum is σ = 190455148800. Its totient is φ = 62624300256.

The previous prime is 110053314431. The next prime is 110053314457. The reversal of 110053314441 is 144413350011.

110053314441 is a `hidden beast` number, since 110 + 0 + 533 + 14 + 4 + 4 + 1 = 666.

It is not a de Polignac number, because 110053314441 - 2¹⁷ = 110053183369 is a prime.

It is a super-2 number, since 2×110053314441² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (110053314431) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 142171 + ... + 490223.

It is an arithmetic number, because the mean of its divisors is an integer number (3967815600).

Almost surely, 2^110053314441 is an apocalyptic number.

It is an amenable number.

110053314441 is a deficient number, since it is larger than the sum of its proper divisors (80401834359).

110053314441 is a wasteful number, since it uses less digits than its factorization.

110053314441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 348315 (or 348302 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 110053314441 its reverse (144413350011), we get a palindrome (254466664452).

The spelling of 110053314441 in words is "one hundred ten billion, fifty-three million, three hundred fourteen thousand, four hundred forty-one".