110055110131 has 4 divisors (see below), whose sum is σ = 110342460672. Its totient is φ = 109767759592.

The previous prime is 110055110129. The next prime is 110055110197. The reversal of 110055110131 is 131011550011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110055110131 - 2¹ = 110055110129 is a prime.

It is a super-2 number, since 2×110055110131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110055110099 and 110055110108.

It is not an unprimeable number, because it can be changed into a prime (110055110111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143674696 + ... + 143675461.

It is an arithmetic number, because the mean of its divisors is an integer number (27585615168).

Almost surely, 2^110055110131 is an apocalyptic number.

110055110131 is a deficient number, since it is larger than the sum of its proper divisors (287350541).

110055110131 is an equidigital number, since it uses as much as digits as its factorization.

110055110131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 287350540.

The product of its (nonzero) digits is 75, while the sum is 19.

Adding to 110055110131 its reverse (131011550011), we get a palindrome (241066660142).

The spelling of 110055110131 in words is "one hundred ten billion, fifty-five million, one hundred ten thousand, one hundred thirty-one".