Base | Representation |
---|---|
bin | 110011001111111001… |
… | …1011100000110101011 |
3 | 101112001221100200011200 |
4 | 1212133303130012223 |
5 | 3300343120303303 |
6 | 122320401455243 |
7 | 10644162066162 |
oct | 1463763340653 |
9 | 345057320150 |
10 | 110055244203 |
11 | 42746352983 |
12 | 193b5341523 |
13 | a4bbaa0298 |
14 | 54806843d9 |
15 | 2ce1dab3a3 |
hex | 199fcdc1ab |
110055244203 has 24 divisors (see below), whose sum is σ = 161007275520. Its totient is φ = 72429580080.
The previous prime is 110055244171. The next prime is 110055244207. The reversal of 110055244203 is 302442550011.
110055244203 is a `hidden beast` number, since 1 + 100 + 552 + 4 + 4 + 2 + 0 + 3 = 666.
It is not a de Polignac number, because 110055244203 - 25 = 110055244171 is a prime.
It is a super-2 number, since 2×1100552442032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (110055244207) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7337850 + ... + 7352832.
It is an arithmetic number, because the mean of its divisors is an integer number (6708636480).
Almost surely, 2110055244203 is an apocalyptic number.
110055244203 is a deficient number, since it is larger than the sum of its proper divisors (50952031317).
110055244203 is a wasteful number, since it uses less digits than its factorization.
110055244203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25399 (or 25396 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 27.
Adding to 110055244203 its reverse (302442550011), we get a palindrome (412497794214).
The spelling of 110055244203 in words is "one hundred ten billion, fifty-five million, two hundred forty-four thousand, two hundred three".
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