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11005561105057 is a prime number
BaseRepresentation
bin1010000000100110111010…
…0011110110101010100001
31102222010021110212002022101
42200021232203312222201
52420303342120330212
635223515053210401
72214061030613521
oct240115643665241
942863243762271
1011005561105057
113563483369502
121298b50190a01
1361aa875b096c
142a0959d77681
1514142e9e9157
hexa026e8f6aa1

11005561105057 has 2 divisors, whose sum is σ = 11005561105058. Its totient is φ = 11005561105056.

The previous prime is 11005561105003. The next prime is 11005561105079. The reversal of 11005561105057 is 75050116550011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7177555377216 + 3828005727841 = 2679096^2 + 1956529^2 .

It is a cyclic number.

It is not a de Polignac number, because 11005561105057 - 219 = 11005560580769 is a prime.

It is a super-2 number, since 2×110055611050572 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11005561103057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502780552528 + 5502780552529.

It is an arithmetic number, because the mean of its divisors is an integer number (5502780552529).

Almost surely, 211005561105057 is an apocalyptic number.

It is an amenable number.

11005561105057 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005561105057 is an equidigital number, since it uses as much as digits as its factorization.

11005561105057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26250, while the sum is 37.

Adding to 11005561105057 its reverse (75050116550011), we get a palindrome (86055677655068).

The spelling of 11005561105057 in words is "eleven trillion, five billion, five hundred sixty-one million, one hundred five thousand, fifty-seven".