Base | Representation |
---|---|
bin | 1010000000101010001110… |
… | …1111100000001101010101 |
3 | 1102222012120122202212222210 |
4 | 2200022203233200031111 |
5 | 2420312204024220003 |
6 | 35224143405144033 |
7 | 2214122113566423 |
oct | 240124357401525 |
9 | 42865518685883 |
10 | 11006453351253 |
11 | 35638a0a85258 |
12 | 129915ab5b019 |
13 | 61ab9a3c0ca9 |
14 | 2a0a02676113 |
15 | 141482ee3503 |
hex | a02a3be0355 |
11006453351253 has 16 divisors (see below), whose sum is σ = 15447930897600. Its totient is φ = 6951319539840.
The previous prime is 11006453351167. The next prime is 11006453351281. The reversal of 11006453351253 is 35215335460011.
It is not a de Polignac number, because 11006453351253 - 29 = 11006453350741 is a prime.
It is a super-2 number, since 2×110064533512532 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11006453351353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1527463 + ... + 4934171.
It is an arithmetic number, because the mean of its divisors is an integer number (965495681100).
Almost surely, 211006453351253 is an apocalyptic number.
It is an amenable number.
11006453351253 is a deficient number, since it is larger than the sum of its proper divisors (4441477546347).
11006453351253 is a wasteful number, since it uses less digits than its factorization.
11006453351253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3463412.
The product of its (nonzero) digits is 162000, while the sum is 39.
The spelling of 11006453351253 in words is "eleven trillion, six billion, four hundred fifty-three million, three hundred fifty-one thousand, two hundred fifty-three".
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