Base | Representation |
---|---|
bin | 1010000000101010001111… |
… | …0010111010000000100001 |
3 | 1102222012120201110012201211 |
4 | 2200022203302322000201 |
5 | 2420312204241241421 |
6 | 35224143440230121 |
7 | 2214122124303343 |
oct | 240124362720041 |
9 | 42865521405654 |
10 | 11006454243361 |
11 | 35638a1534535 |
12 | 129915b30b341 |
13 | 61ab9a644075 |
14 | 2a0a02829293 |
15 | 14148311c9e1 |
hex | a02a3cba021 |
11006454243361 has 2 divisors, whose sum is σ = 11006454243362. Its totient is φ = 11006454243360.
The previous prime is 11006454243287. The next prime is 11006454243437. The reversal of 11006454243361 is 16334245460011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8545571804961 + 2460882438400 = 2923281^2 + 1568720^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11006454243361 is a prime.
It is a super-2 number, since 2×110064542433612 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11006454249361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5503227121680 + 5503227121681.
It is an arithmetic number, because the mean of its divisors is an integer number (5503227121681).
Almost surely, 211006454243361 is an apocalyptic number.
It is an amenable number.
11006454243361 is a deficient number, since it is larger than the sum of its proper divisors (1).
11006454243361 is an equidigital number, since it uses as much as digits as its factorization.
11006454243361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 40.
The spelling of 11006454243361 in words is "eleven trillion, six billion, four hundred fifty-four million, two hundred forty-three thousand, three hundred sixty-one".
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