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11006455143539 is a prime number
BaseRepresentation
bin1010000000101010001111…
…0110010101110001110011
31102222012120210010221112202
42200022203312111301303
52420312210004043124
635224143511413415
72214122135042642
oct240124366256163
942865523127482
1011006455143539
1135638a1a99889
12129915b68426b
1361ab9a89aa0b
142a0a029c1359
151414832495ae
hexa02a3d95c73

11006455143539 has 2 divisors, whose sum is σ = 11006455143540. Its totient is φ = 11006455143538.

The previous prime is 11006455143479. The next prime is 11006455143557. The reversal of 11006455143539 is 93534155460011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11006455143539 is a prime.

It is a super-2 number, since 2×110064551435392 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11006455143493 and 11006455143502.

It is not a weakly prime, because it can be changed into another prime (11006455143589) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5503227571769 + 5503227571770.

It is an arithmetic number, because the mean of its divisors is an integer number (5503227571770).

Almost surely, 211006455143539 is an apocalyptic number.

11006455143539 is a deficient number, since it is larger than the sum of its proper divisors (1).

11006455143539 is an equidigital number, since it uses as much as digits as its factorization.

11006455143539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972000, while the sum is 47.

The spelling of 11006455143539 in words is "eleven trillion, six billion, four hundred fifty-five million, one hundred forty-three thousand, five hundred thirty-nine".