110099131 has 2 divisors, whose sum is σ = 110099132. Its totient is φ = 110099130.

The previous prime is 110099117. The next prime is 110099147. The reversal of 110099131 is 131990011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110099131 is a prime.

It is a super-2 number, since 2×110099131² = 24243637293910322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110099096 and 110099105.

It is not a weakly prime, because it can be changed into another prime (110099831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55049565 + 55049566.

It is an arithmetic number, because the mean of its divisors is an integer number (55049566).

Almost surely, 2^110099131 is an apocalyptic number.

110099131 is a deficient number, since it is larger than the sum of its proper divisors (1).

110099131 is an equidigital number, since it uses as much as digits as its factorization.

110099131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 25.

The square root of 110099131 is about 10492.8133024466. The cubic root of 110099131 is about 479.2858752915.

The spelling of 110099131 in words is "one hundred ten million, ninety-nine thousand, one hundred thirty-one".