Base | Representation |
---|---|
bin | 1010000000110111001111… |
… | …0010000100100111100011 |
3 | 1102222112120220110020121101 |
4 | 2200031303302010213203 |
5 | 2420341331040414403 |
6 | 35225522011135231 |
7 | 2214304445131342 |
oct | 240156362044743 |
9 | 42875526406541 |
10 | 11009943685603 |
11 | 35653222000a5 |
12 | 1299973a44517 |
13 | 61b305554ca5 |
14 | 2a0c54039b59 |
15 | 1415d964171d |
hex | a0373c849e3 |
11009943685603 has 2 divisors, whose sum is σ = 11009943685604. Its totient is φ = 11009943685602.
The previous prime is 11009943685579. The next prime is 11009943685607. The reversal of 11009943685603 is 30658634990011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11009943685603 - 25 = 11009943685571 is a prime.
It is not a weakly prime, because it can be changed into another prime (11009943685607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5504971842801 + 5504971842802.
It is an arithmetic number, because the mean of its divisors is an integer number (5504971842802).
Almost surely, 211009943685603 is an apocalyptic number.
11009943685603 is a deficient number, since it is larger than the sum of its proper divisors (1).
11009943685603 is an equidigital number, since it uses as much as digits as its factorization.
11009943685603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4199040, while the sum is 55.
The spelling of 11009943685603 in words is "eleven trillion, nine billion, nine hundred forty-three million, six hundred eighty-five thousand, six hundred three".
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