Base | Representation |
---|---|
bin | 11001000010001010111011… |
… | …010000011011100000101011 |
3 | 112102211111012112101010112021 |
4 | 121002022323100123200223 |
5 | 103412340440311441133 |
6 | 1030055221142525311 |
7 | 32122325616556354 |
oct | 3102127320334053 |
9 | 472744175333467 |
10 | 110100333312043 |
11 | 3209931a932598 |
12 | 10422222a36837 |
13 | 4958555b73359 |
14 | 1d28c55366d2b |
15 | cade67d3b52d |
hex | 6422bb41b82b |
110100333312043 has 2 divisors, whose sum is σ = 110100333312044. Its totient is φ = 110100333312042.
The previous prime is 110100333312001. The next prime is 110100333312077. The reversal of 110100333312043 is 340213333001011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110100333312043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110100333311999 and 110100333312017.
It is not a weakly prime, because it can be changed into another prime (110100333312083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050166656021 + 55050166656022.
It is an arithmetic number, because the mean of its divisors is an integer number (55050166656022).
Almost surely, 2110100333312043 is an apocalyptic number.
110100333312043 is a deficient number, since it is larger than the sum of its proper divisors (1).
110100333312043 is an equidigital number, since it uses as much as digits as its factorization.
110100333312043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 110100333312043 its reverse (340213333001011), we get a palindrome (450313666313054).
The spelling of 110100333312043 in words is "one hundred ten trillion, one hundred billion, three hundred thirty-three million, three hundred twelve thousand, forty-three".
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