Base | Representation |
---|---|
bin | 11001000010001100100101… |
… | …111000000111010110001011 |
3 | 112102211122211012021222110001 |
4 | 121002030211320013112023 |
5 | 103412403121224200412 |
6 | 1030100114442503431 |
7 | 32122421140166044 |
oct | 3102144570072613 |
9 | 472748735258401 |
10 | 110102122100107 |
11 | 3209a058629535 |
12 | 10422641b04b77 |
13 | 495877c639027 |
14 | 1d28d84b618cb |
15 | cae01edcc957 |
hex | 642325e0758b |
110102122100107 has 2 divisors, whose sum is σ = 110102122100108. Its totient is φ = 110102122100106.
The previous prime is 110102122100083. The next prime is 110102122100167. The reversal of 110102122100107 is 701001221201011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110102122100107 - 231 = 110099974616459 is a prime.
It is a super-2 number, since 2×1101021221001072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110102122100167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55051061050053 + 55051061050054.
It is an arithmetic number, because the mean of its divisors is an integer number (55051061050054).
Almost surely, 2110102122100107 is an apocalyptic number.
110102122100107 is a deficient number, since it is larger than the sum of its proper divisors (1).
110102122100107 is an equidigital number, since it uses as much as digits as its factorization.
110102122100107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 110102122100107 its reverse (701001221201011), we get a palindrome (811103343301118).
The spelling of 110102122100107 in words is "one hundred ten trillion, one hundred two billion, one hundred twenty-two million, one hundred thousand, one hundred seven".
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