Base | Representation |
---|---|
bin | 10000000001011011110… |
… | …000101111000010110011 |
3 | 10220021000010221201001210 |
4 | 100001123300233002303 |
5 | 121014423042130120 |
6 | 2201452122531203 |
7 | 142356034120413 |
oct | 20013360570263 |
9 | 3807003851053 |
10 | 1101051130035 |
11 | 394a537275aa |
12 | 159483966b03 |
13 | 7caa07a7ccc |
14 | 3b410d24643 |
15 | 1d992dd1ce0 |
hex | 1005bc2f0b3 |
1101051130035 has 16 divisors (see below), whose sum is σ = 1761695713440. Its totient is φ = 587222634240.
The previous prime is 1101051130033. The next prime is 1101051130057. The reversal of 1101051130035 is 5300311501011.
It is not a de Polignac number, because 1101051130035 - 21 = 1101051130033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1101051129993 and 1101051130020.
It is not an unprimeable number, because it can be changed into a prime (1101051130033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2610805 + ... + 3003065.
It is an arithmetic number, because the mean of its divisors is an integer number (110105982090).
Almost surely, 21101051130035 is an apocalyptic number.
1101051130035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1101051130035 is a deficient number, since it is larger than the sum of its proper divisors (660644583405).
1101051130035 is a wasteful number, since it uses less digits than its factorization.
1101051130035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 579398.
The product of its (nonzero) digits is 225, while the sum is 21.
Adding to 1101051130035 its reverse (5300311501011), we get a palindrome (6401362631046).
The spelling of 1101051130035 in words is "one trillion, one hundred one billion, fifty-one million, one hundred thirty thousand, thirty-five".
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