Base | Representation |
---|---|
bin | 10000000001011110001… |
… | …011111101000100100011 |
3 | 10220021002222111221221112 |
4 | 100001132023331010203 |
5 | 121020014001213221 |
6 | 2201500135013535 |
7 | 142360040020454 |
oct | 20013613750443 |
9 | 3807088457845 |
10 | 1101091819811 |
11 | 394a74699415 |
12 | 15949550a2ab |
13 | 7caa90537b9 |
14 | 3b4164b712b |
15 | 1d99676d15b |
hex | 1005e2fd123 |
1101091819811 has 2 divisors, whose sum is σ = 1101091819812. Its totient is φ = 1101091819810.
The previous prime is 1101091819781. The next prime is 1101091819837. The reversal of 1101091819811 is 1189181901011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1101091819811 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101091812811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550545909905 + 550545909906.
It is an arithmetic number, because the mean of its divisors is an integer number (550545909906).
Almost surely, 21101091819811 is an apocalyptic number.
1101091819811 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101091819811 is an equidigital number, since it uses as much as digits as its factorization.
1101091819811 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 41.
The spelling of 1101091819811 in words is "one trillion, one hundred one billion, ninety-one million, eight hundred nineteen thousand, eight hundred eleven".
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