Base | Representation |
---|---|
bin | 1010000000111011001010… |
… | …1111100110000110101011 |
3 | 1102222122022112002121211121 |
4 | 2200032302233212012223 |
5 | 2420401012000012224 |
6 | 35230214503440111 |
7 | 2214342562512031 |
oct | 240166257460653 |
9 | 42878275077747 |
10 | 11011000000939 |
11 | 3565814498484 |
12 | 129a009756037 |
13 | 61b44334bc53 |
14 | 2a0d14446551 |
15 | 14164c248be4 |
hex | a03b2be61ab |
11011000000939 has 2 divisors, whose sum is σ = 11011000000940. Its totient is φ = 11011000000938.
The previous prime is 11011000000883. The next prime is 11011000000967. The reversal of 11011000000939 is 93900000011011.
11011000000939 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11011000000939 - 225 = 11010966446507 is a prime.
It is not a weakly prime, because it can be changed into another prime (11011000000139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505500000469 + 5505500000470.
It is an arithmetic number, because the mean of its divisors is an integer number (5505500000470).
Almost surely, 211011000000939 is an apocalyptic number.
11011000000939 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011000000939 is an equidigital number, since it uses as much as digits as its factorization.
11011000000939 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 25.
The spelling of 11011000000939 in words is "eleven trillion, eleven billion, nine hundred thirty-nine", and thus it is an aban number.
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