Base | Representation |
---|---|
bin | 1010000000111011111010… |
… | …1111000111011101001001 |
3 | 1102222122211112200200210111 |
4 | 2200032332233013131021 |
5 | 2420401420001430433 |
6 | 35230250452114321 |
7 | 2214350554631026 |
oct | 240167657073511 |
9 | 42878745620714 |
10 | 11011201201993 |
11 | 3565908020843 |
12 | 129a0650059a1 |
13 | 61b475c36b25 |
14 | 2a0d3305c54d |
15 | 14165ec3ddcd |
hex | a03bebc7749 |
11011201201993 has 2 divisors, whose sum is σ = 11011201201994. Its totient is φ = 11011201201992.
The previous prime is 11011201201967. The next prime is 11011201202101. The reversal of 11011201201993 is 39910210211011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10878044083344 + 133157118649 = 3298188^2 + 364907^2 .
It is a cyclic number.
It is not a de Polignac number, because 11011201201993 - 241 = 8812177946441 is a prime.
It is not a weakly prime, because it can be changed into another prime (11011201261993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505600600996 + 5505600600997.
It is an arithmetic number, because the mean of its divisors is an integer number (5505600600997).
Almost surely, 211011201201993 is an apocalyptic number.
It is an amenable number.
11011201201993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011201201993 is an equidigital number, since it uses as much as digits as its factorization.
11011201201993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 31.
The spelling of 11011201201993 in words is "eleven trillion, eleven billion, two hundred one million, two hundred one thousand, nine hundred ninety-three".
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