Base | Representation |
---|---|
bin | 1010000000111011111101… |
… | …0001000110010011110001 |
3 | 1102222122212011110021112211 |
4 | 2200032333101012103301 |
5 | 2420401424242011233 |
6 | 35230251411052121 |
7 | 2214351023432326 |
oct | 240167721062361 |
9 | 42878764407484 |
10 | 11011210110193 |
11 | 3565912055697 |
12 | 129a067ba1041 |
13 | 61b477a35757 |
14 | 2a0d342dab4d |
15 | 1416608ed5cd |
hex | a03bf4464f1 |
11011210110193 has 2 divisors, whose sum is σ = 11011210110194. Its totient is φ = 11011210110192.
The previous prime is 11011210110137. The next prime is 11011210110283. The reversal of 11011210110193 is 39101101211011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9738593731584 + 1272616378609 = 3120672^2 + 1128103^2 .
It is a cyclic number.
It is not a de Polignac number, because 11011210110193 - 225 = 11011176555761 is a prime.
It is not a weakly prime, because it can be changed into another prime (11011210110133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505605055096 + 5505605055097.
It is an arithmetic number, because the mean of its divisors is an integer number (5505605055097).
Almost surely, 211011210110193 is an apocalyptic number.
It is an amenable number.
11011210110193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011210110193 is an equidigital number, since it uses as much as digits as its factorization.
11011210110193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 22.
The spelling of 11011210110193 in words is "eleven trillion, eleven billion, two hundred ten million, one hundred ten thousand, one hundred ninety-three".
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