Base | Representation |
---|---|
bin | 110011010001100110… |
… | …0010101001100011011 |
3 | 101112012220100022020102 |
4 | 1212203030111030123 |
5 | 3301002144214042 |
6 | 122330152250015 |
7 | 10645452262646 |
oct | 1464314251433 |
9 | 345186308212 |
10 | 110112101147 |
11 | 42775457394 |
12 | 194103a090b |
13 | a4ca7b9749 |
14 | 5488044a5d |
15 | 2ce6d8cb32 |
hex | 19a331531b |
110112101147 has 2 divisors, whose sum is σ = 110112101148. Its totient is φ = 110112101146.
The previous prime is 110112101107. The next prime is 110112101159. The reversal of 110112101147 is 741101211011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110112101147 - 214 = 110112084763 is a prime.
It is not a weakly prime, because it can be changed into another prime (110112101107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056050573 + 55056050574.
It is an arithmetic number, because the mean of its divisors is an integer number (55056050574).
Almost surely, 2110112101147 is an apocalyptic number.
110112101147 is a deficient number, since it is larger than the sum of its proper divisors (1).
110112101147 is an equidigital number, since it uses as much as digits as its factorization.
110112101147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 110112101147 its reverse (741101211011), we get a palindrome (851213312158).
The spelling of 110112101147 in words is "one hundred ten billion, one hundred twelve million, one hundred one thousand, one hundred forty-seven".
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