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110112113100313 is a prime number
BaseRepresentation
bin11001000010010101111001…
…011000110000011000011001
3112102212121121111010101011201
4121002111321120300120121
5103413034101423202223
61030104450104354201
732123223545245402
oct3102257130603031
9472777544111151
10110112113100313
11320a33152568a5
121042456ba75961
1349596b24c4c7c
141d29651a209a9
15cae4070adead
hex642579630619

110112113100313 has 2 divisors, whose sum is σ = 110112113100314. Its totient is φ = 110112113100312.

The previous prime is 110112113100257. The next prime is 110112113100361. The reversal of 110112113100313 is 313001311211011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100313785768329 + 9798327331984 = 10015677^2 + 3130228^2 .

It is a cyclic number.

It is not a de Polignac number, because 110112113100313 - 217 = 110112112969241 is a prime.

It is a super-2 number, since 2×1101121131003132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110112113100373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056056550156 + 55056056550157.

It is an arithmetic number, because the mean of its divisors is an integer number (55056056550157).

Almost surely, 2110112113100313 is an apocalyptic number.

It is an amenable number.

110112113100313 is a deficient number, since it is larger than the sum of its proper divisors (1).

110112113100313 is an equidigital number, since it uses as much as digits as its factorization.

110112113100313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 110112113100313 its reverse (313001311211011), we get a palindrome (423113424311324).

The spelling of 110112113100313 in words is "one hundred ten trillion, one hundred twelve billion, one hundred thirteen million, one hundred thousand, three hundred thirteen".