Base | Representation |
---|---|
bin | 11001000010010101111010… |
… | …100101001010011100010011 |
3 | 112102212121122212210222202002 |
4 | 121002111322211022130103 |
5 | 103413034122040130003 |
6 | 1030104452101544215 |
7 | 32123224210430114 |
oct | 3102257245123423 |
9 | 472777585728662 |
10 | 110112133130003 |
11 | 320a3325597464 |
12 | 1042457671506b |
13 | 49596b66b8a64 |
14 | 1d2965455620b |
15 | cae408c18a88 |
hex | 64257a94a713 |
110112133130003 has 2 divisors, whose sum is σ = 110112133130004. Its totient is φ = 110112133130002.
The previous prime is 110112133129979. The next prime is 110112133130053. The reversal of 110112133130003 is 300031331211011.
It is a weak prime.
It is an emirp because it is prime and its reverse (300031331211011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110112133130003 - 224 = 110112116352787 is a prime.
It is not a weakly prime, because it can be changed into another prime (110112133130053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056066565001 + 55056066565002.
It is an arithmetic number, because the mean of its divisors is an integer number (55056066565002).
Almost surely, 2110112133130003 is an apocalyptic number.
110112133130003 is a deficient number, since it is larger than the sum of its proper divisors (1).
110112133130003 is an equidigital number, since it uses as much as digits as its factorization.
110112133130003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 110112133130003 its reverse (300031331211011), we get a palindrome (410143464341014).
The spelling of 110112133130003 in words is "one hundred ten trillion, one hundred twelve billion, one hundred thirty-three million, one hundred thirty thousand, three".
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