1101123132433 has 2 divisors, whose sum is σ = 1101123132434. Its totient is φ = 1101123132432.

The previous prime is 1101123132419. The next prime is 1101123132467. The reversal of 1101123132433 is 3342313211011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 897475811904 + 203647320529 = 947352^2 + 451273^2 .

It is an emirp because it is prime and its reverse (3342313211011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1101123132433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1101123132398 and 1101123132407.

It is not a weakly prime, because it can be changed into another prime (1101123112433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550561566216 + 550561566217.

It is an arithmetic number, because the mean of its divisors is an integer number (550561566217).

Almost surely, 2^{1101123132433} is an apocalyptic number.

It is an amenable number.

1101123132433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101123132433 is an equidigital number, since it uses as much as digits as its factorization.

1101123132433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1101123132433 its reverse (3342313211011), we get a palindrome (4443436343444).

The spelling of 1101123132433 in words is "one trillion, one hundred one billion, one hundred twenty-three million, one hundred thirty-two thousand, four hundred thirty-three".