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11011255033 = 50383218551
BaseRepresentation
bin10100100000101001…
…00110101011111001
31001102101121201020111
422100110212223321
5140022340130113
65020345224321
7536604060232
oct122024465371
931371551214
1011011255033
114740625979
1221737920a1
13106636852c
147665a0089
15446a6413d
hex290526af9

11011255033 has 4 divisors (see below), whose sum is σ = 11011523968. Its totient is φ = 11010986100.

The previous prime is 11011254973. The next prime is 11011255049. The reversal of 11011255033 is 33055211011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11011255033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11011254995 and 11011255013.

It is not an unprimeable number, because it can be changed into a prime (11011255933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58893 + ... + 159658.

It is an arithmetic number, because the mean of its divisors is an integer number (2752880992).

Almost surely, 211011255033 is an apocalyptic number.

It is an amenable number.

11011255033 is a deficient number, since it is larger than the sum of its proper divisors (268935).

11011255033 is an equidigital number, since it uses as much as digits as its factorization.

11011255033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 268934.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 11011255033 its reverse (33055211011), we get a palindrome (44066466044).

The spelling of 11011255033 in words is "eleven billion, eleven million, two hundred fifty-five thousand, thirty-three".

Divisors: 1 50383 218551 11011255033