11011902990001 has 4 divisors (see below), whose sum is σ = 11591476831600. Its totient is φ = 10432329148404.

The previous prime is 11011902989951. The next prime is 11011902990019. The reversal of 11011902990001 is 10009920911011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11011902990001 is a prime.

It is a super-3 number, since 3×11011902990001³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11011902990061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289786920771 + ... + 289786920808.

It is an arithmetic number, because the mean of its divisors is an integer number (2897869207900).

Almost surely, 2^{11011902990001} is an apocalyptic number.

It is an amenable number.

11011902990001 is a deficient number, since it is larger than the sum of its proper divisors (579573841599).

11011902990001 is an equidigital number, since it uses as much as digits as its factorization.

11011902990001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 579573841598.

The product of its (nonzero) digits is 1458, while the sum is 34.

The spelling of 11011902990001 in words is "eleven trillion, eleven billion, nine hundred two million, nine hundred ninety thousand, one".