11012000000993 has 2 divisors, whose sum is σ = 11012000000994. Its totient is φ = 11012000000992.

The previous prime is 11012000000917. The next prime is 11012000001029. The reversal of 11012000000993 is 39900000021011.

11012000000993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9265497669184 + 1746502331809 = 3043928^2 + 1321553^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012000000993 - 2⁸ = 11012000000737 is a prime.

It is not a weakly prime, because it can be changed into another prime (11012000300993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506000000496 + 5506000000497.

It is an arithmetic number, because the mean of its divisors is an integer number (5506000000497).

Almost surely, 2^{11012000000993} is an apocalyptic number.

It is an amenable number.

11012000000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012000000993 is an equidigital number, since it uses as much as digits as its factorization.

11012000000993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 26.

The spelling of 11012000000993 in words is "eleven trillion, twelve billion, nine hundred ninety-three", and thus it is an aban number.