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11012112003 = 33670704001
BaseRepresentation
bin10100100000101111…
…10111111010000011
31001102110020020210010
422100113313322003
5140023100041003
65020415440003
7536614256544
oct122027677203
931373206703
1011012112003
114741060812
122173b26003
1310665a8609
147667444cb
15446b83003
hex2905f7e83

11012112003 has 4 divisors (see below), whose sum is σ = 14682816008. Its totient is φ = 7341408000.

The previous prime is 11012111993. The next prime is 11012112011. The reversal of 11012112003 is 30021121011.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11012112003 - 210 = 11012110979 is a prime.

It is a super-2 number, since 2×110121120032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11012112003.

It is not an unprimeable number, because it can be changed into a prime (11012112403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1835351998 + ... + 1835352003.

It is an arithmetic number, because the mean of its divisors is an integer number (3670704002).

Almost surely, 211012112003 is an apocalyptic number.

11012112003 is a deficient number, since it is larger than the sum of its proper divisors (3670704005).

11012112003 is an equidigital number, since it uses as much as digits as its factorization.

11012112003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3670704004.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 11012112003 its reverse (30021121011), we get a palindrome (41033233014).

The spelling of 11012112003 in words is "eleven billion, twelve million, one hundred twelve thousand, three".

Divisors: 1 3 3670704001 11012112003