Base | Representation |
---|---|
bin | 11001000010011110010010… |
… | …001111101110111011010011 |
3 | 112102220110212012101101000121 |
4 | 121002132102033232323103 |
5 | 103413211023221200201 |
6 | 1030112535535531111 |
7 | 32123663004422014 |
oct | 3102362217567323 |
9 | 472813765341017 |
10 | 110121120100051 |
11 | 320a7117499035 |
12 | 10426264389a97 |
13 | 495a4b9556308 |
14 | 1d29c67d3900b |
15 | cae782bbe9a1 |
hex | 6427923eeed3 |
110121120100051 has 2 divisors, whose sum is σ = 110121120100052. Its totient is φ = 110121120100050.
The previous prime is 110121120099989. The next prime is 110121120100127. The reversal of 110121120100051 is 150001021121011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110121120100051 - 27 = 110121120099923 is a prime.
It is a super-2 number, since 2×1101211201000512 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110121120099998 and 110121120100034.
It is not a weakly prime, because it can be changed into another prime (110121120100951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060560050025 + 55060560050026.
It is an arithmetic number, because the mean of its divisors is an integer number (55060560050026).
Almost surely, 2110121120100051 is an apocalyptic number.
110121120100051 is a deficient number, since it is larger than the sum of its proper divisors (1).
110121120100051 is an equidigital number, since it uses as much as digits as its factorization.
110121120100051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 16.
Adding to 110121120100051 its reverse (150001021121011), we get a palindrome (260122141221062).
The spelling of 110121120100051 in words is "one hundred ten trillion, one hundred twenty-one billion, one hundred twenty million, one hundred thousand, fifty-one".
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