Base | Representation |
---|---|
bin | 1010000000111111101001… |
… | …1001101010101010010011 |
3 | 1102222202102022021021100201 |
4 | 2200033322121222222103 |
5 | 2420410442231240422 |
6 | 35230534051200031 |
7 | 2214414431236354 |
oct | 240177231525223 |
9 | 42882368237321 |
10 | 11012202211987 |
11 | 3566281074429 |
12 | 129a2a42a6017 |
13 | 61b5a5438932 |
14 | 2a0dc9d8dd2b |
15 | 1416bca6e727 |
hex | a03fa66aa93 |
11012202211987 has 2 divisors, whose sum is σ = 11012202211988. Its totient is φ = 11012202211986.
The previous prime is 11012202211943. The next prime is 11012202212003. The reversal of 11012202211987 is 78911220221011.
11012202211987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11012202211987 is a prime.
It is not a weakly prime, because it can be changed into another prime (11012202611987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506101105993 + 5506101105994.
It is an arithmetic number, because the mean of its divisors is an integer number (5506101105994).
Almost surely, 211012202211987 is an apocalyptic number.
11012202211987 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012202211987 is an equidigital number, since it uses as much as digits as its factorization.
11012202211987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 37.
Adding to 11012202211987 its reverse (78911220221011), we get a palindrome (89923422432998).
The spelling of 11012202211987 in words is "eleven trillion, twelve billion, two hundred two million, two hundred eleven thousand, nine hundred eighty-seven".
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