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110122221422281 is a prime number
BaseRepresentation
bin11001000010011111010011…
…111000111100011011001001
3112102220120200221201100002211
4121002133103320330123021
5103413220302141003111
61030113241121025121
732124032206463005
oct3102372370743311
9472816627640084
10110122221422281
11320a76321267a2
12104265111851a1
13495a63377aa83
141d29d302dd705
15cae7e9717521
hex6427d3e3c6c9

110122221422281 has 2 divisors, whose sum is σ = 110122221422282. Its totient is φ = 110122221422280.

The previous prime is 110122221422273. The next prime is 110122221422363. The reversal of 110122221422281 is 182224122221011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110093815353600 + 28406068681 = 10492560^2 + 168541^2 .

It is a cyclic number.

It is not a de Polignac number, because 110122221422281 - 23 = 110122221422273 is a prime.

It is a super-2 number, since 2×1101222214222812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110122221432281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55061110711140 + 55061110711141.

It is an arithmetic number, because the mean of its divisors is an integer number (55061110711141).

Almost surely, 2110122221422281 is an apocalyptic number.

It is an amenable number.

110122221422281 is a deficient number, since it is larger than the sum of its proper divisors (1).

110122221422281 is an equidigital number, since it uses as much as digits as its factorization.

110122221422281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4096, while the sum is 31.

Adding to 110122221422281 its reverse (182224122221011), we get a palindrome (292346343643292).

The spelling of 110122221422281 in words is "one hundred ten trillion, one hundred twenty-two billion, two hundred twenty-one million, four hundred twenty-two thousand, two hundred eighty-one".