110122224241131 has 24 divisors (see below), whose sum is σ = 160137190671120. Its totient is φ = 72920699447616.

The previous prime is 110122224241103. The next prime is 110122224241151. The reversal of 110122224241131 is 131142422221011.

110122224241131 is a `hidden beast` number, since 1 + 1 + 0 + 1 + 2 + 2 + 2 + 242 + 411 + 3 + 1 = 666.

110122224241131 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 110122224241131 - 2⁶ = 110122224241067 is a prime.

It is a super-2 number, since 2×110122224241131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110122224241095 and 110122224241104.

It is not an unprimeable number, because it can be changed into a prime (110122224241151) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20039976 + ... + 24936821.

It is an arithmetic number, because the mean of its divisors is an integer number (6672382944630).

Almost surely, 2^{110122224241131} is an apocalyptic number.

110122224241131 is a deficient number, since it is larger than the sum of its proper divisors (50014966429989).

110122224241131 is a wasteful number, since it uses less digits than its factorization.

110122224241131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44978635 (or 44978632 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 27.

Adding to 110122224241131 its reverse (131142422221011), we get a palindrome (241264646462142).

The spelling of 110122224241131 in words is "one hundred ten trillion, one hundred twenty-two billion, two hundred twenty-four million, two hundred forty-one thousand, one hundred thirty-one".