Base | Representation |
---|---|
bin | 10000000001100110011… |
… | …011111100111011110001 |
3 | 10220021110121221222210021 |
4 | 100001212123330323301 |
5 | 121020304414400111 |
6 | 2201522001403441 |
7 | 142363340343445 |
oct | 20014633747361 |
9 | 3807417858707 |
10 | 1101230231281 |
11 | 395035835a64 |
12 | 159513939581 |
13 | 7cacb925a8b |
14 | 3b42aa26825 |
15 | 1d9a39add71 |
hex | 100666fcef1 |
1101230231281 has 2 divisors, whose sum is σ = 1101230231282. Its totient is φ = 1101230231280.
The previous prime is 1101230231201. The next prime is 1101230231363. The reversal of 1101230231281 is 1821320321011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 983103978256 + 118126253025 = 991516^2 + 343695^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1101230231281 is a prime.
It is a super-2 number, since 2×11012302312812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1101230231201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550615115640 + 550615115641.
It is an arithmetic number, because the mean of its divisors is an integer number (550615115641).
Almost surely, 21101230231281 is an apocalyptic number.
It is an amenable number.
1101230231281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101230231281 is an equidigital number, since it uses as much as digits as its factorization.
1101230231281 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 1101230231281 its reverse (1821320321011), we get a palindrome (2922550552292).
The spelling of 1101230231281 in words is "one trillion, one hundred one billion, two hundred thirty million, two hundred thirty-one thousand, two hundred eighty-one".
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