Base | Representation |
---|---|
bin | 1010000001000000000011… |
… | …1101101000011010011001 |
3 | 1102222202200222102111012011 |
4 | 2200100000331220122121 |
5 | 2420411203422201012 |
6 | 35230553022545521 |
7 | 2214420236061226 |
oct | 240200075503231 |
9 | 42882628374164 |
10 | 11012312303257 |
11 | 3566328228651 |
12 | 129a3151382a1 |
13 | 61b5c21a36b5 |
14 | 2a0dda84a94d |
15 | 1416c75691a7 |
hex | a0400f68699 |
11012312303257 has 2 divisors, whose sum is σ = 11012312303258. Its totient is φ = 11012312303256.
The previous prime is 11012312303233. The next prime is 11012312303273. The reversal of 11012312303257 is 75230321321011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5990863245376 + 5021449057881 = 2447624^2 + 2240859^2 .
It is a cyclic number.
It is not a de Polignac number, because 11012312303257 - 215 = 11012312270489 is a prime.
It is not a weakly prime, because it can be changed into another prime (11012312300257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506156151628 + 5506156151629.
It is an arithmetic number, because the mean of its divisors is an integer number (5506156151629).
Almost surely, 211012312303257 is an apocalyptic number.
It is an amenable number.
11012312303257 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012312303257 is an equidigital number, since it uses as much as digits as its factorization.
11012312303257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 11012312303257 its reverse (75230321321011), we get a palindrome (86242633624268).
The spelling of 11012312303257 in words is "eleven trillion, twelve billion, three hundred twelve million, three hundred three thousand, two hundred fifty-seven".
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