Base | Representation |
---|---|
bin | 10000000001100110100… |
… | …111010100011011111011 |
3 | 10220021110211120101101002 |
4 | 100001212213110123323 |
5 | 121020311200224011 |
6 | 2201522145315215 |
7 | 142363404564164 |
oct | 20014647243373 |
9 | 3807424511332 |
10 | 1101233211131 |
11 | 395037490849 |
12 | 159514935b0b |
13 | 7cacc42a1c1 |
14 | 3b42b1a076b |
15 | 1d9a3d9bc3b |
hex | 100669d46fb |
1101233211131 has 2 divisors, whose sum is σ = 1101233211132. Its totient is φ = 1101233211130.
The previous prime is 1101233211041. The next prime is 1101233211173. The reversal of 1101233211131 is 1311123321011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1101233211131 is a prime.
It is a super-2 number, since 2×11012332111312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1101233211181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550616605565 + 550616605566.
It is an arithmetic number, because the mean of its divisors is an integer number (550616605566).
Almost surely, 21101233211131 is an apocalyptic number.
1101233211131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101233211131 is an equidigital number, since it uses as much as digits as its factorization.
1101233211131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1101233211131 its reverse (1311123321011), we get a palindrome (2412356532142).
The spelling of 1101233211131 in words is "one trillion, one hundred one billion, two hundred thirty-three million, two hundred eleven thousand, one hundred thirty-one".
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