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11012341354603 is a prime number
BaseRepresentation
bin1010000001000000001010…
…1100011101000001101011
31102222202210000002110010221
42200100002230131001223
52420411233341321403
635230555541350511
72214421041026101
oct240200254350153
942882700073127
1011012341354603
113566342670326
12129a322a08437
1361b5c8205944
142a100064dc71
151416c9da6dbd
hexa0402b1d06b

11012341354603 has 2 divisors, whose sum is σ = 11012341354604. Its totient is φ = 11012341354602.

The previous prime is 11012341354579. The next prime is 11012341354699. The reversal of 11012341354603 is 30645314321011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11012341354603 is a prime.

It is a super-2 number, since 2×110123413546032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11012341354103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506170677301 + 5506170677302.

It is an arithmetic number, because the mean of its divisors is an integer number (5506170677302).

Almost surely, 211012341354603 is an apocalyptic number.

11012341354603 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012341354603 is an equidigital number, since it uses as much as digits as its factorization.

11012341354603 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 11012341354603 its reverse (30645314321011), we get a palindrome (41657655675614).

The spelling of 11012341354603 in words is "eleven trillion, twelve billion, three hundred forty-one million, three hundred fifty-four thousand, six hundred three".