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110130001142434 = 271331617143110457
BaseRepresentation
bin11001000010100110100011…
…100110001110001010100010
3112102221022210010122001212021
4121002212203212032022202
5103413332220243024214
61030121005111252054
732124426044142610
oct3102464346161242
9472838703561767
10110130001142434
11320aa96461a689
1210427b2267a02a
13495b2a3485c90
141d2a46b6266b0
15caeb026ee924
hex6429a398e2a2

110130001142434 has 256 divisors, whose sum is σ = 216843209146368. Its totient is φ = 40788437760000.

The previous prime is 110130001142401. The next prime is 110130001142641. The reversal of 110130001142434 is 434241100031011.

It is a junction number, because it is equal to n+sod(n) for n = 110130001142399 and 110130001142408.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 10531696134 + ... + 10531706590.

It is an arithmetic number, because the mean of its divisors is an integer number (847043785728).

Almost surely, 2110130001142434 is an apocalyptic number.

110130001142434 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

110130001142434 is a deficient number, since it is larger than the sum of its proper divisors (106713208003934).

110130001142434 is a wasteful number, since it uses less digits than its factorization.

110130001142434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11073.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 110130001142434 its reverse (434241100031011), we get a palindrome (544371101173445).

The spelling of 110130001142434 in words is "one hundred ten trillion, one hundred thirty billion, one million, one hundred forty-two thousand, four hundred thirty-four".