Base | Representation |
---|---|
bin | 10000000001101010100… |
… | …111001111110011111011 |
3 | 10220021122111210220102221 |
4 | 100001222213033303323 |
5 | 121020430334113201 |
6 | 2201532543304511 |
7 | 142365151050466 |
oct | 20015247176373 |
9 | 3807574726387 |
10 | 1101300301051 |
11 | 395071344465 |
12 | 1595332ab137 |
13 | 7cb102ba292 |
14 | 3b4360662dd |
15 | 1d9a9c004a1 |
hex | 1006a9cfcfb |
1101300301051 has 2 divisors, whose sum is σ = 1101300301052. Its totient is φ = 1101300301050.
The previous prime is 1101300300983. The next prime is 1101300301061. The reversal of 1101300301051 is 1501030031011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1101300301051 - 27 = 1101300300923 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101300301061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550650150525 + 550650150526.
It is an arithmetic number, because the mean of its divisors is an integer number (550650150526).
Almost surely, 21101300301051 is an apocalyptic number.
1101300301051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101300301051 is an equidigital number, since it uses as much as digits as its factorization.
1101300301051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 16.
Adding to 1101300301051 its reverse (1501030031011), we get a palindrome (2602330332062).
The spelling of 1101300301051 in words is "one trillion, one hundred one billion, three hundred million, three hundred one thousand, fifty-one".
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