Base | Representation |
---|---|
bin | 1010000001000011000100… |
… | …0111001111010011001011 |
3 | 1102222211210021111020200121 |
4 | 2200100301013033103023 |
5 | 2420414332223100303 |
6 | 35231205121244111 |
7 | 2214446245345054 |
oct | 240206107172313 |
9 | 42884707436617 |
10 | 11013120128203 |
11 | 3566702223476 |
12 | 129a4bb793637 |
13 | 61b6c066611b |
14 | 2a1075c5172b |
15 | 1417234399bd |
hex | a04311cf4cb |
11013120128203 has 2 divisors, whose sum is σ = 11013120128204. Its totient is φ = 11013120128202.
The previous prime is 11013120128117. The next prime is 11013120128237. The reversal of 11013120128203 is 30282102131011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11013120128203 - 221 = 11013118031051 is a prime.
It is not a weakly prime, because it can be changed into another prime (11013121128203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506560064101 + 5506560064102.
It is an arithmetic number, because the mean of its divisors is an integer number (5506560064102).
Almost surely, 211013120128203 is an apocalyptic number.
11013120128203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013120128203 is an equidigital number, since it uses as much as digits as its factorization.
11013120128203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 11013120128203 its reverse (30282102131011), we get a palindrome (41295222259214).
The spelling of 11013120128203 in words is "eleven trillion, thirteen billion, one hundred twenty million, one hundred twenty-eight thousand, two hundred three".
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