110131232110113 has 4 divisors (see below), whose sum is σ = 146841642813488. Its totient is φ = 73420821406740.

The previous prime is 110131232110063. The next prime is 110131232110121. The reversal of 110131232110113 is 311011232131011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 110131232110113 - 2¹² = 110131232106017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 110131232110113.

It is not an unprimeable number, because it can be changed into a prime (110131232810113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18355205351683 + ... + 18355205351688.

It is an arithmetic number, because the mean of its divisors is an integer number (36710410703372).

Almost surely, 2^{110131232110113} is an apocalyptic number.

It is an amenable number.

110131232110113 is a deficient number, since it is larger than the sum of its proper divisors (36710410703375).

110131232110113 is an equidigital number, since it uses as much as digits as its factorization.

110131232110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36710410703374.

The product of its (nonzero) digits is 108, while the sum is 21.

Adding to 110131232110113 its reverse (311011232131011), we get a palindrome (421142464241124).

The spelling of 110131232110113 in words is "one hundred ten trillion, one hundred thirty-one billion, two hundred thirty-two million, one hundred ten thousand, one hundred thirteen".